Question

A solid in the form of a light circular cylindrical with a hemi-spherical one end and a cone at other end . Radius of common base is 3.53.5cm. find total surface area of the solid.

Answer 1

Total surface area = (curved surface area of hemisphere+curved surface area of cylander +surface area of cone0

$\begin{array}{c}=\left(2\pi r^2+2\pi rh+\pi rl\right)=\pi \left(2\times 3.5\times 3.5+2+2\times 3.5\times 10+3.5\times 6\right)\\ =\frac{22}{7}\left(7\times 3.5+70+7\times 3\right)\\ =\frac{22}{7}\times 7\left(3.5+10+3\right)\\ =16.5\times 22=363c{m}^2\end{array}$