A solid iron ball of mass $500 g$ is dropped in a beaker of mercury. What will be the apparent weight of ball?

490 g

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0 g

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500 g

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None of the above

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Solution

The correct option is B $0 g$
The density of iron ball is less than the density of mercury.
$∴$ When an iron ball is dropped in beaker containing mercury, the iron ball will float.
This implies that the buoyant force exerted by mercury is equal to the weight of the iron ball.
$∵$ Apparent weight = weight of object - buoyant force,
$∴$ Apparent weight of iron ball $= 0 g$

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A solid iron ball of mass 500g is dropped in a beaker of mercury. What will be the apparent weight of ball?

A solid iron ball of mass $500 g$ is dropped in a beaker of mercury. What will be the apparent weight of ball?