A solid iron cuboidal block of dimensions 4.4m×2.6m×1m is recast into a hollow cylindrical pipe of internal radius 30cm and thickness 5cm. Find the length of the pipe.
A
112m
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B
110m
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C
114m
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D
116m
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Solution
The correct option is B112m Volume of rectangle =lbh=(4.4)(2.6)(1)=11.44m3=11440000 cm3 ....(1) Internal radius of cylinder =r cm Outer Radius of cylinder =R cm ⇒R=r+ width ⇒R=(30+5) cm =35 cm Volume of hollow cylinder =π(R2−r2)h
=π(352−302)h
=π(325)h cm2 ....(2) Equating (1) and (2), we get ⇒π(325h)=11440000 ⇒h=11200cm=112 m