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Question

A solid iron cuboidal block of dimensions 4.4 m×2.6 m×1 m is recast into a hollow cylindrical pipe of internal radius 30 cm and thickness 5 cm. Find the length of the pipe.

A
112 m
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B
110 m
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C
114 m
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D
116 m
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Solution

The correct option is B 112 m
Volume of rectangle =lbh=(4.4)(2.6)(1)=11.44m3=11440000 cm3 ....(1)
Internal radius of cylinder = r cm
Outer Radius of cylinder = R cm
R=r+ width
R=(30+5) cm =35 cm
Volume of hollow cylinder =π(R2r2)h
=π(352302)h
=π(325)h cm2 ....(2)
Equating (1) and (2), we get
π(325h)=11440000
h=11200cm=112 m

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