A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. What is the mass of the pole, given that 1cm3 of iron has approximately 8 g mass. (Use π=3.14)
Radius of the big cylinder
=r1=242=12 cm
Radius of the small cylinder
r=8 cm
Height of the big cylinder
=h1=220 cm
Height of small cylinder
=h=60 cm
Volume of the big cylinder
=π.(r1)2.h1=3.14×(12)2×220=99475.2 cm3
Volume of the small cylinder
=π.r2.h=3.14×(8)2×60=12057.6 cm3
∴Volume of the Pole = Volume of the big cylinder + Volume of the small cylinder
=99475.2+12057.6=111532.8 cm3
1 cm3 of iron = 8 g
111532.8 cm3 of iron=111532.8×8
=892262.4 g=892.262 kg