A solid is formed by the elements X, Y, and Z. X atoms form an FCC lattice with Y atoms occupying all tetrahedral voids. Z atoms occupying half the octahedral voids. The formula of the solid is :

X_{2} Y_{4} Z

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

X Y_{2} Z_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X_{4} Y_{2} Z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X_{4} Y Z_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $X_{2} Y_{4} Z$
$Z_{e f f}$ of $X = 6 \times \frac{1}{2} + 8 \times \frac{1}{8} = 4$
$Z_{e f f}$ of $Y =$ All Tetrehedral voids= $8$
$Z_{e f f}$ of $Z = \frac{1}{2} \times$ octahedral voids= $\frac{1}{2} \times 4 = 2$
Formula $X_{4} Y_{8} Z_{2} = X_{2} Y_{4} Z$

Suggest Corrections

Similar questions

Q. A solid has three types of atoms

X, Y

and

Z

X

forms an

F C C

lattice with

Y

atoms occupying all the tetrahedral voids and

Z

atoms occupying half of the octahedral voids. The formula of the solid is

Q. A solid is formed and it has three types of atoms X, Y, Z. X forms an FCC lattice with Y atoms occupying one-forth of tetrahedral viods and Z atoms occupying half of the octahedral voids. The formula of the solid is?

Q. A solid is formed and it has three types of atoms, X, Y, Z. X forms a FCC lattice with Y atoms occupying all the tetrahedral voids and Z atoms occupying half the octrahedral voids. The formula of the solid is:

Q. A solid is formed and it has three types of atoms X, Y and Z. X forms FCC lattice with Y atoms occupying all the tetrahedral voids and Z atoms occupying half the octahedral voids. If the formula of the solid is

X_{a} Y_{b} Z_{c}

, then the values of a, b and c are, respectively :

A compound formed by elements X, Y, Z . Atoms of Y forms ccp lattice and X occupies half the octahedral voids and Z occupies half the tetrahedral voids. Find the formula of the compound?

Join BYJU'S Learning Program

A solid is formed by the elements X, Y, and Z. X atoms form an FCC lattice with Y atoms occupying all tetrahedral voids. Z atoms occupying half the octahedral voids. The formula of the solid is :

The correct option is A X2Y4ZZeff of X=6×12+8×18=4Zeff of Y= All Tetrehedral voids=8Zeff of Z=12× octahedral voids=12×4=2Formula X4Y8Z2=X2Y4Z

The correct option is A $X_{2} Y_{4} Z$
$Z_{e f f}$ of $X = 6 \times \frac{1}{2} + 8 \times \frac{1}{8} = 4$
$Z_{e f f}$ of $Y =$ All Tetrehedral voids= $8$
$Z_{e f f}$ of $Z = \frac{1}{2} \times$ octahedral voids= $\frac{1}{2} \times 4 = 2$
Formula $X_{4} Y_{8} Z_{2} = X_{2} Y_{4} Z$