Question

A solid is in the form of a right circular cylinder, with a hemisphere at one end and a cone at the other end. The radius of the common base is $8cm$ and the heights of the cylindrical and conical portions are $10cm$ and $6cm$ respectively. Find the total surface area of the solid. (Use $\pi =22/7$)

Answer 1

Height of the cylindrical part and cone are $10cmand6cm$respectively

Radius of cone , cylinder and hemi sphere$=3.5cm$

$r=3.5$cm for both Cylinder and cone

The area of canvas required=Surface area of hemishphere,cylinder and cone parts of tent

$A=2\pi r^2+2\pi rh+\pi r\left(\sqrt{h^2+r^2}\right)$

$A=2\pi \times 3.5\times 3.5+2\pi \times 3.5\times 10+\pi \times 3.5\left(\sqrt{{3.5}^2+6^2}\right)$

$A=373.3c{m}^2$