A solid is made up of elements A, B, C and D. Atoms A, B, C, and D are located at corners, face-centres, body-centre and edge-centres respectively. If atoms touching one of the body-diagonal planes of symmetry are removed then the formula of compound is

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Q. In a unit cell, atoms

A, B, C

and

D

are present at corners, face-centres, body-centre and edge-centres respectively. If atoms touching one of the plane passing through two diagonally opposite edges are removed, then formula of compound is:

In a unit cell atoms A B C and D are present at corners face centres bodycentre and edge centres respectively.if atoms touching one of the plane passing through two diagonally opposite edges are removed then formula of compound is

Q. A compound is formed by the elements X, Y . It has a cubic structure with atoms of element X occupying corners and half the face centres of the cube. Atoms of element Y are present at the remaining face centres and body centre.

What will be the simplest formula of the compound if all the atoms are removed from one body diagonal of the cube?

Q. Atoms A, B, C and D are present at corners, face centres, body centre and edge centres respectively. If atoms touching one of the 2-fold axis, 3-fold axis and 4-fold axis are removed, then total number of atoms remaining per unit cell is

X + \frac{1}{4}

.The value of X is

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