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Standard XII

Physics

Motional EMF

A solid metal...

Question

A solid metal cube of edge length $2 c m$ is moving in a positive $y$ direction at a constant speed of $6 m / s$ . There is a uniform magnetic field of $0.1 T$ in the positive $z - d i r e c t i o n$ . The potential difference between the two faces of the cube perpendicular to the $x - a x i s$ , is:

6 m V

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1 m V

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12 m V

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2 m V

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Solution

The correct option is C $12 m V$
Potential difference between two faces perpendicular to x-axis will be
$l . (\to V \times \to B) = 12 m V$ .

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A solid metal cube of edge length 2 cm is moving in a positive y direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive z−direction. The potential difference between the two faces of the cube perpendicular to the x−axis, is:

The correct option is C 12 mVPotential difference between two faces perpendicular to x-axis will bel.(→V×→B)=12 mV.

The correct option is C $12 m V$
Potential difference between two faces perpendicular to x-axis will be
$l . (\to V \times \to B) = 12 m V$ .