You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Force on a Current Element

A solid metal...

Question

A solid metal cube of edge length $2 cm$ is moving in a positive $y -$ direction at a constant speed of $6 m/s$ . There is a uniform magnetic field of $0.1 T$ in the positive $z -$ direction. The potential difference between the two faces of the cube, perpendicular to the x-axis, is:

2 mV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 mV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 mV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 mV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $12 mV$
Potential difference between two faces perpendicular to $x -$ axis
$= B l V = 2 \times 10^{- 2} (6 \times 0.1) = 12 mV$

Hence, $(A)$ is the correct answer.

Suggest Corrections

Similar questions

Q. A solid metal cube of edge length

2 c m

is moving in a positive

y

direction at a constant speed of

6 m / s

. There is a uniform magnetic field of

0.1 T

in the positive

z - d i r e c t i o n

. The potential difference between the two faces of the cube perpendicular to the

x - a x i s

, is:

Q. There is a uniform magnetic field

B

directed in negative

z

direction. A conductor

A B C

has length

A B = l_{1}

, parallel to the

x -

axis, and length

B C = l_{2}

parallel to the

y -

axis.

A B C

moves in the

x y

plane with velocity

v_{x}^i + v_{y}^j

. The potential difference between

A

and

C

is proportional to

Q. A proton moves in the positive

z -

direction after being accelerated from rest through a potential difference

V

. The proton then passes through a region with a uniform electric field

E

in the positive x-direction and a uniform magnetic field

B

in the positive

y -

direction, but the proton's trajectory is not affected. If the experiment were repeated using a potential difference of

2 V

, the proton would then be

Q. A cube of edge

a

has its edges parallel to

x, y

and

z -

axis of rectangular coordinate system. A uniform electric field

E

parallel to

y -

axis and a uniform magnetic field is parallel to

x -

axis. The rate at which energy flows through each face of the cube is:

Q. An electron is moving with a uniform speed in the X - Y plane in a straight path along the negative X direction. If a uniform magnetic field is applied parallel along the positive z-axis, the electron will :

Join BYJU'S Learning Program

A solid metal cube of edge length 2 cm is moving in a positive y−direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive z−direction. The potential difference between the two faces of the cube, perpendicular to the x-axis, is:

The correct option is C 12 mVPotential difference between two faces perpendicular to x−axis =BlV=2×10−2(6×0.1)=12 mV Hence, (A) is the correct answer.

A solid metal cube of edge length $2 cm$ is moving in a positive $y -$ direction at a constant speed of $6 m/s$ . There is a uniform magnetic field of $0.1 T$ in the positive $z -$ direction. The potential difference between the two faces of the cube, perpendicular to the x-axis, is:

The correct option is C $12 mV$
Potential difference between two faces perpendicular to $x -$ axis
$= B l V = 2 \times 10^{- 2} (6 \times 0.1) = 12 mV$

Hence, $(A)$ is the correct answer.