Question

A solid metallic cuboid of dimensions 9 m × 8 m × 2 m is melted and recast into solid cubes of edge 2 m. Find the number of cubes so formed. [CBSE 2017]

Answer 1

The volume of solid metallic cuboid is $9\times 8\times 2=144{\mathrm{m}}^3.$
This cuboid has been recasted into solid cubes of edge 2 m whose volume is given by $2^3=8{\mathrm{m}}^3.$
Therefore, the total number of cubes so formed $=\frac{\mathrm{the}\mathrm{volume}\mathrm{of}\mathrm{solid}\mathrm{metallic}\mathrm{cuboid}}{\mathrm{the}\mathrm{volume}\mathrm{of}\mathrm{solid}\mathrm{cubes}}=\frac{144}{8}=18.$