A solid object of mass 600 g when completely immersed in a liquid of density 2.5 g/cm $^{3}$ experiences a buoyant force of 19 . 6 N.Find the volume of the object .(g = 9 . 8 m/s $^{2}$

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Solution

$\begin{matrix} f_{B} = f_{l} v_{l} g 19.6 = 2500 \times v_{1} \times 9.8 v_{1} = v_{5} (b e c a u s e c o m p l e t i n g s u b m e r s u a l) v_{l} = \frac{2}{2500} m^{3} = \frac{2}{2500} \times 1000 \times 1000 = 800 c m^{3} \end{matrix}$

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A solid object of mass 600 g when completely immersed in a liquid of density 2.5 g/cm3 experiences a buoyant force of 19 . 6 N.Find the volume of the object .(g = 9 . 8 m/s2

fB=flvlg19.6=2500×v1×9.8v1=v5(becausecompletingsubmersual)vl=22500m3=22500×1000×1000=800cm3

A solid object of mass 600 g when completely immersed in a liquid of density 2.5 g/cm $^{3}$ experiences a buoyant force of 19 . 6 N.Find the volume of the object .(g = 9 . 8 m/s $^{2}$

$\begin{matrix} f_{B} = f_{l} v_{l} g 19.6 = 2500 \times v_{1} \times 9.8 v_{1} = v_{5} (b e c a u s e c o m p l e t i n g s u b m e r s u a l) v_{l} = \frac{2}{2500} m^{3} = \frac{2}{2500} \times 1000 \times 1000 = 800 c m^{3} \end{matrix}$