A solid object weighs 50gf in air and 30gf in water.
i) Find the buoyant force acting on the object.
ii) Find the volume and the density of the object.
iii) Now water is replaced by a liquid of relative density 2.5. Find the apparent weight?Will the solid object sink or float in the liquid? Justify your answer.

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Solution

Weight in air = 50 gf weight in water = 30 gf
Buoyant force = weight in air - weight in water
= 50gf - 30gf = 20gf
now Relative density of liquid = $\frac{l o s s o f w t . i n l i q u i d}{l o s s o f w t . i n w a t e r}$
2.5 = $\frac{50 g f - a p p a r e n t w t .}{50 g f - 30 g f}$
50 = 50gf - apparent weight
apparent weight = 0
Hence body will float in liquid of Relative density 2.5

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