A solid of mass 0.15 kg is heated from 10 °C to 90 °C. If the specific heat capacity of the solid is 390 J kg^-1 °C^-1, find the heat absorbed by the solid.

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Solution

Given:
The mass (m) of the solid = 0.15 kg.
Rise in temperature (θ_R) = 90 - 10 = 80 °C.
The specific heat capacity of the solid (c) = 390 J kg^-1 °C^-1.
Finding heat absorbed (H) by the body:
We know that heat absorbed by a cold body (H) = mcθ_R, where m is the mass of the body, θ_Ris the rise in temperature of the body and c is the specific heat capacity.
By substituting the given values in the above expression, we get
$H = 0.15 x 390 x 80 = 4, 680 J$
Hence, the heat absorbed by the body is 4,680 J.

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