A solid of mass $0.15 k g$ is heated from $10 ° C$ to $90 ° C$ . If the specific heat capacity of the solid is $390 J k g^{- 1} ° C^{- 1}$ , find the heat absorbed by the solid.

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Solution

Step 1: Given data
mass $(m) = 0.15 k g$
the temperature change from $10 ° C$ to $90 ° C$
Sp. heat capacity $(c) = 390 J k g^{- 1} ° C^{- 1}$
heat absorbed=?
Step 2: calculating the heat absorbed
Rise in temperature $(θ_{R}) = (90 - 10) ° C = 80 ° C$
Now, heat absorbed $= m c θ_{R}$
$= 0.15 k g \times 390 J k g^{- 1} ° C^{- 1} \times 80 ° C = 4680 J$
The heat absorbed by the solid is $4680 J$ .

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A solid of mass 0.15kgis heated from10°C to90°C. If the specific heat capacity of the solid is390Jkg-1°C-1, find the heat absorbed by the solid.

A solid of mass $0.15 k g$ is heated from $10 ° C$ to $90 ° C$ . If the specific heat capacity of the solid is $390 J k g^{- 1} ° C^{- 1}$ , find the heat absorbed by the solid.