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Standard XII

Physics

Specific Heat Capacity

A solid of ma...

Question

A solid of mass 250 g at $90^{0} C$ is dropped in a calorimeter containing 100 g of water at $15^{0} C$ . The resulting temperature of mixture becomes $40^{0} C$ . The mass of calorimeter is 100 g and its specific heat capacity is 0.1 cal/ $g^{0} C$ . Find the specific heat capacity of the solid.

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Solution

Heat absorbed by the ''calorimeter + water'' system is equal to the heat released by the solid.
Specific heat of water $S_{w} = 1 c a l / g^{o} C$
So, $m_{w} S_{w} (40 - 15) + m_{c} S_{c} (40 - 15) = m_{s} S_{s} (90 - 40)$
Or $100 \times 1 \times 25 + 100 \times 0.1 \times 25 = 250 \times S_{s} \times 50$
$⟹ S_{s} = 0.22 c a l / g^{o} C$

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A solid of mass 250 g at 900C is dropped in a calorimeter containing 100 g of water at 150C. The resulting temperature of mixture becomes 400C. The mass of calorimeter is 100 g and its specific heat capacity is 0.1 cal/g0C. Find the specific heat capacity of the solid.

Heat absorbed by the ''calorimeter + water'' system is equal to the heat released by the solid.Specific heat of water Sw=1 cal/goCSo, mwSw(40−15)+mcSc(40−15)=msSs(90−40) Or 100×1×25+100×0.1×25=250×Ss×50⟹ Ss=0.22 cal/goC

A solid of mass 250 g at $90^{0} C$ is dropped in a calorimeter containing 100 g of water at $15^{0} C$ . The resulting temperature of mixture becomes $40^{0} C$ . The mass of calorimeter is 100 g and its specific heat capacity is 0.1 cal/ $g^{0} C$ . Find the specific heat capacity of the solid.