A solid of mass 50 g at 150- C is placed in 100 g of water at 11- C when the final temperature recorded is 20- C- Find the specific heat capacity of solid- SHC of water is 4-2 J - g - C

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Heating Curve of Ice

A solid of ma...

Question

A solid of mass 50g at $150^{\circ} C$ is placed in 100 g of water at $11^{\circ} C$ when the final temperature recorded is $20^{\circ} C$ . Find the specific heat capacity of solid. SHC of water is $4.2 J / g^{\circ} C$

Open in App

Solution

Given:
Hot body: Cold body:
m = 50 g m = 100 g
c = ? c = 4.2
t = 150 c t = 11 c
Final temp = 20 c
m.c.t = m.c.t
$50 \times c \times (150 - 20) = 100 \times 4.2 \times (20 - 11)$
$50 \times c \times 130 = 420 \times 9$
$c = 420 \times \frac{9}{50} \times 130$
$c = 0.58 J / g / d e g r e e c$

Suggest Corrections

Similar questions

Q. A solid of mass

50

g at

150^{o}

C is placed in

100

g of water at

11^{o}

C, when the final temperature recorded is

20^{o}

C. Find the specific heat capacity of the solid. (Specific heat capacity of water

4.2

/ g^{o}

50 g

of a certain metal at

150^{\circ} C

is immersed in

100 g

of water at

11^{\circ} C

. The final temperature is

20^{\circ} C

. Find the specific heat capacity of the metal.
Specific heat capacity of water is

4.2 J g^{- 1} K^{- 1}

Q. A hot solid of mass

60 g

100^{o} C

is placed in 150 g of water at

20^{o} C

. The final steady temperature recorded is

25^{o} C

. Calculate the specific heat capacity of the solid.
[Specific heat capacity of water = 4200 J

k g^{- 1}^{o} C^{- 1}

A mass of 50 g of a certain metal at $150^{\circ} C$ is immersed in 100 g of water at $11^{\circ} C$ . The final temperature is $20^{\circ} C$ . Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is 4.2 J $g^{- 1} K^{- 1}$ .

A hot solid of mass 60 g at 100 $^{\circ} C$ is placed in 150 g of water at 20 $^{\circ} C$ . The final temperature recorded is 25 $^{\circ} C$ . Calculate the specific heat of solid. (Specific heat of water = 4200J/kg/ $^{\circ} C$ )

Join BYJU'S Learning Program

A solid of mass 50g at 150∘C is placed in 100 g of water at 11∘C when the final temperature recorded is 20∘C. Find the specific heat capacity of solid. SHC of water is 4.2 J/g∘C

Given: Hot body: Cold body: m = 50 g m = 100 g c = ? c = 4.2 t = 150 c t = 11 c Final temp = 20 c m.c.t = m.c.t 50×c×(150−20)=100×4.2×(20−11) 50×c×130=420×9 c=420×950×130 c=0.58 J/g/degree c

A solid of mass 50g at $150^{\circ} C$ is placed in 100 g of water at $11^{\circ} C$ when the final temperature recorded is $20^{\circ} C$ . Find the specific heat capacity of solid. SHC of water is $4.2 J / g^{\circ} C$

Given:
Hot body: Cold body:
m = 50 g m = 100 g
c = ? c = 4.2
t = 150 c t = 11 c
Final temp = 20 c
m.c.t = m.c.t
$50 \times c \times (150 - 20) = 100 \times 4.2 \times (20 - 11)$
$50 \times c \times 130 = 420 \times 9$
$c = 420 \times \frac{9}{50} \times 130$
$c = 0.58 J / g / d e g r e e c$