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Byju's Answer

Standard IV

Science

Change of State

A solid of ma...

Question

A solid of mass $50 g$ at $150 ° C$ is placed in $100 g$ of water at $11 ° C,$ when the final temperature recorded is $20 ° C$ . Find the specific heat capacity of the solid.

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Solution

Step 1: Organised table of the given data
Substance Mass S.H.C Initial Temperature Final Temperature=x
Solid $50 g$ $x$ $150 ° C$ $θ_{F} = 150 - 11 = 139 ° C$
Water $100 g$ $4.2 J g^{- 1} ° C^{- 1}$ $11 ° C$ $θ_{R} = 20 - 11 = 9 ° C$
Step 2: Calculating the heat energy
The heat released by the hot solid is given as
$m c θ_{F} = 50 \times x \times 139 = 6950 x$
The heat absorbed by the water is given as
$m c θ_{R} = 100 \times 4.2 \times 9 = 3780$
Step3: Calculating the specific heat f capacity of solid
The heat released by solid= Heat absorbed by water
$6950 x = 3780 x = 0.58$
Hence specific heat capacity of solid is $0.58 J g^{- 1} ° C^{- 1}$

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A mass of 50 g of a certain metal at $150^{\circ} C$ is immersed in 100 g of water at $11^{\circ} C$ . The final temperature is $20^{\circ} C$ . Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is 4.2 J $g^{- 1} K^{- 1}$ .

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Substance	Mass	S.H.C	Initial Temperature	Final Temperature=x
Solid	$50 g$	$x$	$150 ° C$	$θ_{F} = 150 - 11 = 139 ° C$
Water	$100 g$	$4.2 J g^{- 1} ° C^{- 1}$	$11 ° C$	$θ_{R} = 20 - 11 = 9 ° C$

A solid of mass 50g at 150°C is placed in 100g of water at 11°C, when the final temperature recorded is 20°C. Find the specific heat capacity of the solid.

A solid of mass $50 g$ at $150 ° C$ is placed in $100 g$ of water at $11 ° C,$ when the final temperature recorded is $20 ° C$ . Find the specific heat capacity of the solid.