Question

A solid shaft of 80 mm diameter is transmitting 100 kW of power at 200 r.p.m. The maximum shear stress induced in the shaft will nearly be

• A. $60N/m{m}^2$
• B. $56N/m{m}^2$
• C. $52N/m{m}^2$
• D. $48N/m{m}^2$

Answer 1

The correct option is D $48N/m{m}^2$

d = 800 mm, P = 100 kN
N = 200 rpm

$P=\frac{2\pi NT}{60}$

$\Rightarrow T=\frac{100\times {10}^3\times 60}{2\pi \times 200}N-m$

${\tau }_{max}=\frac{T}{Z_p}=\frac{\left(\frac{100\times {10}^3\times 60}{2\pi \times 200}\right)N-mm}{\frac{\pi \times {80}^3}{16}}$

$=46.875N/m{m}^2$