Question

A solid shaft of circular cross-section is subjected to a torque T which produces a maximum shear stress $f_s$ in the shaft. The diameter of the shaft should be

• A. $\sqrt{\frac{\pi f_s}{16T}}$
• B. $3\sqrt{\frac{\pi f_s}{16T}}$
• C. $\sqrt{\frac{16T}{\pi f_s}}$
• D. $3\sqrt{\frac{16T}{\pi f_s}}$

Answer 1

The correct option is D $3\sqrt{\frac{16T}{\pi f_s}}$

$f_s=\frac{16}{\pi d^3}T$

$\therefore d=3\sqrt{\frac{16T}{\pi f_s}}$