Question

A solid shaft rotating at 180 rpm subjected to a mean torque of 5000 N-m. What is the power transmitted by the shaft in kW?

• A. $25\pi$
• B. $20\pi$
• C. $60\pi$
• D. $30\pi$

Answer 1

The correct option is D $30\pi$

The power transmitted by the shaft is given by

$P=\frac{2\pi NT}{60}$

$=\frac{2\pi \times 180\times 5000\times {10}^{-3}}{60}$

$=30\pi kW$