A solid silver piece is immersed in water contained in a measuring cylinder. The level of water rises from $50 m l$ to $62 m l$ . Find the volume of the silver piece.

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Solution

Given,
Initial level of water, $V_{1} = 50 m l$
Final level of water after silver is immersed in water, $V_{2} = 62 m l$
Understanding the problem
When a silver piece is immersed in water, it displaces the volume of water equal to its own volume so as to occupy the space of water.
Therefore,
Volume of silver piece = Volume of water displaced by silver when completely immersed in water
And,
Volume of displaced water = Final level of water - Initial level of water
So, volume of silver piece (V):
$V = V_{2} - V_{1}$
V = 62 ml - 50 ml = 12 ml = 12 cubic centimetre
(Since 1 ml = 1 cubic centimetre)

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A solid silver piece is immersed in water contained in a measuring cylinder. The level of water rises from 50 ml to 62 ml. Find the volume of the silver piece.

A solid silver piece is immersed in water contained in a measuring cylinder. The level of water rises from $50 m l$ to $62 m l$ . Find the volume of the silver piece.