A solid sphere of mass 0.1 Kg and radius 2 cm rolls down an inclined plane 1.4 m in length (slope 1 in 10). Starting from rest its final velocity will be
A
1.4 m/sec
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B
0.14 m/sec
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C
14 m/sec
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D
0.7 m/sec
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Solution
The correct option is A1.4 m/sec We have tanθ=110 or θ=0.099 or sinθ=0.099 Thus height of the of incline is given as 0.099×1.4=0.14m Using conservation of energy we have mg(0.14)=12mv2+15mv2 or 0.14g=710v2 or v=√0.14×9.81×107 or v=1.4m/s