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Question

A solid sphere of mass 2 kg radius 0.5 m is rolling with an initial speed of 1 ms1 goes up an inclined plane which makes an angle of 30 with the horizontal plane, without slipping. How long will the sphere take to return to the starting point A?

A
0.80 s
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B
0.60 s
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C
0.52 s
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D
0.57 s
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Solution

The correct option is D 0.57 s
Acceleration of ball, a=gsinθ1+k2R2 where k is radius of gyration.

For a solid sphere, k2R2=25
a=9.8sin301+25
a=3.5 m/sec2

Time of ascent is given by
v=u+at
0=13.5 t
t=13.5 s
Time of decent
t=13.5 sec.
Due to symmetry of motion.
Total time, T=23.5=0.57 s

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