wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A solid sphere of mass 2 kg radius 0.5 m is rolling with an initial speed of 1 ms1 goes up an inclined plane which makes an angle of 30 with the horizontal plane, without slipping. How long will the sphere take to return to the starting point A?

A
0.80 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.60 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.52 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.57 s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.57 s
Acceleration of ball, a=gsinθ1+k2R2 where k is radius of gyration.

For a solid sphere, k2R2=25
a=9.8sin301+25
a=3.5 m/sec2

Time of ascent is given by
v=u+at
0=13.5 t
t=13.5 s
Time of decent
t=13.5 sec.
Due to symmetry of motion.
Total time, T=23.5=0.57 s

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Jumping Off Cliffs
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon