A solid sphere of mass 2kg radius 0.5m is rolling with an initial speed of 1ms−1 goes up an inclined plane which makes an angle of 30∘ with the horizontal plane, without slipping. How long will the sphere take to return to the starting point A?
A
0.80s
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B
0.60s
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C
0.52s
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D
0.57s
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Solution
The correct option is D0.57s Acceleration of ball, a=gsinθ1+k2R2 where k is radius of gyration.
For a solid sphere, k2R2=25 a=9.8sin30∘1+25 a=3.5m/sec2
Time of ascent is given by v=u+at 0=1−3.5t t=13.5s
Time of decent t=13.5sec.
Due to symmetry of motion.
Total time, T=23.5=0.57s