A solid sphere of radius 20 cm is subjected to a uniform pressure of 106 Nm -2- If the bulk modulus of the solid is 1-7 - 1011 N m -2- the decrease in the volume of the solid is approximately equal toA- 0-2 cm 3B- 0-3 cm 3C- 0-5 cm 3D- 0-4 cm 3

The correct option is A 0.2 cm^3 Given, radius of the sphere, r = 20 cm = 0.2 m Volume of sphere, V= 4 π r^3/3 Now, decrease in volume, Δ V = V Δ P/B=4 π/3×(0. ...

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Standard VII

Physics

Bulk Modulus

A solid spher...

Question

A solid sphere of radius 20 cm is subjected to a uniform pressure of $10^{6} N m^{- 2}$ . If the bulk modulus of the solid is $1.7 \times 10^{11} N m^{- 2}$ , the decrease in the volume of the solid is approximately equal to

$0.2 c m^{3}$

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$0.3 c m^{3}$

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$0.4 c m^{3}$

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$0.5 c m^{3}$

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Solution

The correct option is A
$0.2 c m^{3}$

Given, radius of the sphere, r = 20 cm = 0.2 m
Volume of sphere, $V = \frac{4 π r^{3}}{3}$
Now, decrease in volume, $Δ V = \frac{V Δ P}{B} = \frac{4 π}{3} \times \frac{(0.2)^{3} \times 10^{6}}{1.7 \times 10^{11}}$
$≃ 0.2 \times 10^{- 6} m^{3} = 0.2 c m^{3}$
Hence, the correct choice is (a).

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A solid sphere of radius 20 cm is subjected to a uniform pressure of 106 Nm−2. If the bulk modulus of the solid is 1.7×1011 Nm−2, the decrease in the volume of the solid is approximately equal to

The correct option is A 0.2 cm3 Given, radius of the sphere, r = 20 cm = 0.2 m Volume of sphere, V=4πr33 Now, decrease in volume, ΔV=VΔPB=4π3×(0.2)3×1061.7×1011 ≃0.2×10−6 m3=0.2 cm3 Hence, the correct choice is (a).

A solid sphere of radius 20 cm is subjected to a uniform pressure of $10^{6} N m^{- 2}$ . If the bulk modulus of the solid is $1.7 \times 10^{11} N m^{- 2}$ , the decrease in the volume of the solid is approximately equal to