A solid sphere of radius 20 cm is subjected to a uniform pressure of 10-6 -Nm-2- If the bulk modulus of the solid is 1-7 - 10-11-Nm-2- the decrease in the volume of the solid is approximately equal to 0-2-cm-3-0-3-cm-3-0-5-cm-3-0-4-cm-3-

The correct option is A 0.2 cm^3 Given, radius of the sphere, r = 20 cm = 0.2 m Volume of sphere, V= 4 π r^3/3 Now, decrease in volume, Δ V = V Δ P/B=4 π/3×(0. ...

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Standard VII

Physics

Bulk Modulus

A solid spher...

Question

A solid sphere of radius 20 cm is subjected to a uniform pressure of $10^{6} N m^{- 2}$ . If the bulk modulus of the solid is $1.7 \times 10^{11} N m^{- 2}$ , the decrease in the volume of the solid is approximately equal to

$0.2 c m^{3}$

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$0.3 c m^{3}$

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$0.4 c m^{3}$

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$0.5 c m^{3}$

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Solution

The correct option is A
$0.2 c m^{3}$

Given, radius of the sphere, r = 20 cm = 0.2 m
Volume of sphere, $V = \frac{4 π r^{3}}{3}$
Now, decrease in volume, $Δ V = \frac{V Δ P}{B} = \frac{4 π}{3} \times \frac{(0.2)^{3} \times 10^{6}}{1.7 \times 10^{11}}$
$≃ 0.2 \times 10^{- 6} m^{3} = 0.2 c m^{3}$
Hence, the correct choice is (a).

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