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Question

A solid sphere of radius r is melted and recast into the shape of a solid cone of height r. The radius of the base of the cone is:

A
r
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B
2r
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C
r2
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D
r2
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Solution

The correct option is B 2r
Radius of sphere =r
Volume of sphere =43πr3
Let radius of the base of cone be R and height is h=r
Now volume of cone =13πr2h =13πR2r
But Volume of cone = Volume of sphere
13πR2r=43πr3R2=4r2R=2r
Hence, radius of base of cone =2r

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