wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

A solid sphere of volume V and density ρ floats at the interface of two immiscible liquids of densities ρ1and ρ2 respectively. If ρ1<ρ<ρ2, then find out the ratio of volume of the parts of the sphere in upper and lower liquids is

A
ρ2ρ1ρρ1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
ρ+ρ1ρ+ρ2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
ρ+ρ2ρ+ρ1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
ρ1ρ2ρ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A ρ2ρ1ρρ1
Let vnth part of the sphere is inside the liquid with density ρ2
vρg=vnρ2g+v(11n)ρ1gρρ2n=(11n)ρ1ρρ1=ρ2ρ1nn=ρ2ρ1ρρ1

990823_877457_ans_895e04b88d894e60bf23765fb274d00b.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Archimedes' Principle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon