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Question

A solid sphere rests on a horizontal surface, A horizontal impulse is applied at height h from the centre. The sphere starts rotating just after the application of impulse. The ratio h/R will be


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A
12
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B
25
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C
14
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D
15
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Solution

The correct option is B 25
Let the force act for time t.
So, F×t=I .......(1)
Inertia of solid sphere is I=2MR2/5 .......(2)
writing torque about center,
Iα=Fh .........(3)
As linear motion is given as F=ma ..........(4)
and v=ωR
From (1),(2),(3) and (4),
hR=25

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