Question

A solid sphere roll down an inclined plane inclined at an angle $\theta$ with horizontal. Find its linear acceleration $\overrightarrow{a}$.

Answer 1

Linear acceleration of the object rolling down the inclined plane $a=\frac{g\sin \theta }{1+K}$

where, $\theta$ is the angle of inclined plane.

For, solid sphere $K=\frac{2}{5}$

$⟹a=\frac{g\sin \theta }{1+\frac{2}{5}}=\frac{5g\sin \theta }{7}$