The correct option is B Translational speed will be same, but time of descent will be different
In case of pure rolling, mechanical energy remains conserved.
Height of inclined planes are equal,
∴Loss in PE =Gain in KERot+Gain in KETrans
Since sphere is starting from rest ωi=0, vi=0
⇒Translational velocity of sphere will be same while descent, in both the cases.
Now, acceleration of sphere down the inclined plane:
a∝sin θ
s=ut+12at2, u=0
∴ Time of descent will be different in both cases.