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Question

A solid sphere weight 40 N in water and 45 N in a liquid of relative density 0.75. Relative density of sphere will be

A
3
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B
2
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C
1
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D
4
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Solution

The correct option is A 3
If apparent weight is w in a liquid It means w is the weight of the sphere minus the weight of the liquid the sphere's volume displaces.

So w=ρsVsgρlVsg

for water w1=ρsVsgρwVsg
40=ρsVsg1×Vsg (1)

for liquid w1=ρsVsgρwVsg
45=ρsVsg0.75×Vsg (2)

Solving equations we get

ρs=3

Hence relative density of sphere is 3.

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