A solid suspended from a hook of a spring balance weights $96 g f$ in air. When the solid is immersed in a liquid, the weight recorded by the spring balance is $72 g f$ . The buoyant force acting on solid is:

95 g f

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72 g f

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24 g f

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none of these

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Solution

The correct option is C $24 g f$
Weight in air $= 96 g f$
Weight in water $= 72 g f$
$∴$ weight loss $= (96 - 72) g f = 24 g f$
We know that buoyant force exerted is equal to weight loss.
So, buoyant force exerted $= 24 g f$

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A solid suspended from a hook of a spring balance weights 96 gf in air. When the solid is immersed in a liquid, the weight recorded by the spring balance is 72 gf. The buoyant force acting on solid is:

The correct option is C 24 gfWeight in air =96 gfWeight in water =72 gf∴ weight loss =(96−72) gf=24 gfWe know that buoyant force exerted is equal to weight loss.So, buoyant force exerted =24 gf

A solid suspended from a hook of a spring balance weights $96 g f$ in air. When the solid is immersed in a liquid, the weight recorded by the spring balance is $72 g f$ . The buoyant force acting on solid is:

The correct option is C $24 g f$
Weight in air $= 96 g f$
Weight in water $= 72 g f$
$∴$ weight loss $= (96 - 72) g f = 24 g f$
We know that buoyant force exerted is equal to weight loss.
So, buoyant force exerted $= 24 g f$