Question

A solid uniform ball having volume V and density $\rho$ floats at the interface of two unmixible liquids as shown in Fig. The densities of the upper and the lower liquids are ${\rho }_1$ and ${\rho }_2$ respectively, such that ${\rho }_1<\rho <{\rho }_2$. What fraction of the volume of the ball will be in the lower liquid :-

• A. $\frac{\rho -{\rho }_2}{{\rho }_1-{\rho }_2}$
• B. $\frac{{\rho }_1}{{\rho }_1-{\rho }_2}$
• C. $\frac{{\rho }_1-\rho }{{\rho }_1-{\rho }_2}$
• D. $\frac{{\rho }_1-{\rho }_2}{{\rho }_2}$

Answer 1

The correct option is C $\frac{{\rho }_1-\rho }{{\rho }_1-{\rho }_2}$