A solid Weighs 0.144 kg f in air, 0.128 kg f in water, and 0.136 kg f in liquid. Calculate density Of solid as Well as a liquid.

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Solution

Step 1 Given,
Mass of solid in air = $0.144 k g$
Mass of solid in water = $0.128 k g$
Step 2 Formula used,
Loss of weight = $M a s s o f s o l i d i n a i r - m a s s o f s o l i d i n w a t e r$
Loss of weight in water is due to the weight of displaced water that has the same volume of solid.
Displaced volume of water = $\frac{m a s s}{d e n s i t y}$
Step 3, Solution
Loss of weight in water = $0.144 - 0.128 = 16 g$
Displaced volume of water = $\frac{16 \times 10^{- 3}}{1000} = 16 \times 10^{- 6} m^{3}$
Volume of solid = $16 \times 10^{- 6} m^{3}$
Density of solid = $\frac{0.144}{(16 \times 10^{- 6})} = 9000 k g / m^{3}$
Loss of weight in liquid = displaced liquid mass $= 0.144 - 0.136 = 0.008 k g$
Density of liquid = $\frac{0.008}{16 \times 10^{- 6}} = 2000 k g / m^{3}$
Hence, density of solid is $9000 k g / m^{3}$ and that of liquid is $2000 k g / m^{3}$

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