A solid weighs 32 g-f in air and 28.8 g-f in water. The R.D. of the solid is

8.9

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29.12

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Solution

The correct option is B 10
$R e l a t i v e d e n s i t y = \frac{w t . o f s o l i d}{l o s s i n w e i g h t o f s o l i d i n w a t e r}$
$= \frac{32}{32 - 28.8} = \frac{32}{3.2}$
Relative density = 10

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