A solid weighs 32 gf in air and 28.8 gf in water. The relative density of the solid is.

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32.6

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Solution

The correct option is B 10
Relative density of solid = $\frac{m a s s o f s u b s t a n c e}{m a s s o f s u b s t a n c e i n w a t e r l o s t}$
= $\frac{32}{32 - 28.8} = \frac{32}{3.2}$
Relative density = 10

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A solid weighs 32 gf in air and 28.8 gf in water. The relative density of the solid is.

The correct option is B 10Relative density of solid = massofsubstancemassofsubstanceinwaterlost = 3232−28.8=323.2Relative density = 10

The correct option is B 10
Relative density of solid = $\frac{m a s s o f s u b s t a n c e}{m a s s o f s u b s t a n c e i n w a t e r l o s t}$
= $\frac{32}{32 - 28.8} = \frac{32}{3.2}$
Relative density = 10