Question

A solid weighs 32gf in air and 28.8gf in water.The Relative Density of the solid is:

• A. 8.9
• B. 10
• C. 29.12
• D. 20

Answer 1

The correct option is B 10

$\text{Relative Density}=\frac{\text{Weight in air}}{\text{Loss of weight in water}}$

Weight in air $32gf$

Loss of weight in water $=32-28.8=3.2gf$

Hence $\text{Relative Density}=\frac{32}{32-28.8}=\frac{32}{3.2}=10$

Therefore the correct option is (B).