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Question

A solid wood door has dimensions; height = 2m, width = 0.8m, thickness = 0.04m. Its thermal conductivity is K=0.04 Js1m1(C)1. The inside air temperature is 20C and outside air temperature is 10C. What is the rate of heat flow through the door, assuming the surface temperatures are those of the surrounding air.

A
148 watts
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B
48 watts
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C
408 watts
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D
11. 48 watts
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Solution

The correct option is B 48 watts
dQdt=KA(T2T1)x=0.04×(hw)(T2T1)t=0.04×2×0.8×[(273+20)(27310)]0.04=48 watts

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