A solid X which is insoluble in water, weight 180 g in the air and 150 g in water. What is the relative density of the solid X?

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Solution

The correct option is A
6

Weight of the solid X in air, $W_{a i r} = 180 g m$
Weight of the solid X in water, $W_{w a t e r} = 150 g m$
Relative Density of solid X = ?
As, Relative density of solid $= \frac{Weight of solid in air}{Loss of weight of solid in water} = \frac{180}{(180 - 150)} = \frac{180}{30} = 6$
Therefore, relative density of X is 6.

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A solid X which is insoluble in water, weight 180 g in the air and 150 g in water. What is the relative density of the solid X?

The correct option is A 6 Weight of the solid X in air, Wair=180gm Weight of the solid X in water, Wwater=150gm Relative Density of solid X = ? As, Relative density of solid =Weight of solid in airLoss of weight of solid in water=180(180−150)=18030=6 Therefore, relative density of X is 6.