A solid $X^{+} Y^{-}$ has a bcc structure. If the distance of closest approach between the two atoms is $173$ pm, the edge length of the cell is:

200

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{3} / \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

142.2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $200$ pm
For BCC lattice $r = 0.433 a$
Lattice is half of the body diagonal , that is $\frac{\sqrt{3} a}{2} = 173 p m$
Thus
$a = \frac{173 \times 2}{\sqrt{3}}$
$= \frac{173 \times 2}{1.73}$
$= 200 p m$

Suggest Corrections

Similar questions

1.73 \circ A

\sqrt{3} = 1.73

X Y

A^{+} B^{-}

173 p m

X^{+} Y^{-}

1.73 ˚ A

Join BYJU'S Learning Program