A solid $X Y$ has bcc structure. If the distance of closest approach between the two atoms is 173 pm, the edge length of the cell is :

200

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\frac{\sqrt{3}}{\sqrt{2}}

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142.2

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\sqrt{2}

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Solution

The correct option is A $200$ pm
Distance of closest approach= $\frac{\sqrt{3}}{2 a}$ {for BCC}

$a =$ edge length of cell

Given = $\frac{\sqrt{3}}{2 a} = 173$ pm

$⟹ a = \frac{2 \times 173}{\sqrt{3}} = 200$ pm

Hence, the correct option is A.

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