A solution consists of CH3COOH(pKa=4.74) and CH3COONa. If the pH of the solution reaches 6.74, the percentage dissociation of CH3COOH is:
A
50%
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B
1%
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C
99%
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D
None of these
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Solution
The correct option is C 99% pH=pKa+logsaltacid 6.74=4.74+logsaltacid ∴logsaltacid=2, Hence [CH3COO−]=100[CH3COOH] cα=100(c−cα) α=100101=0.99 the percentage dissociation of CH3COOH is 99%