A solution containing 0-011 kg of barium nitrate in 0-1 kg of water boils at 100-46-C- Calculate the degree of ionization of the salt- Kb water - 0-52 K kg mol-1- write the value to the nearest integer

Δ T_b = i K_bm 0.46 = i×0.52×0.011×10^3/0.1×261 i = 2.098 α = i 1/n 1 ⇒2.098 1/3 1; α ⇒ 0.55 ...

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A solution containing $0.011 k g$ of barium nitrate in $0.1 k g$ of water boils at ${100.46}^{\circ} C$ . Calculate the degree of ionization of the salt. $K_{b} (w a t e r) = 0.52 K k g m o l^{- 1}$ . (write the value to the nearest integer)

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