Question

A solution containing $0.2$ moles of ferric chloride is allowed to react with $0.24$ mole of sodium hydroxide. Choose the correct statement.

• A. Limiting reagent for this reaction is $NaOH$
• B. $0.08$ moles of $Fe(OH{)}_3$ is formed
• C. $0.12$ moles of $FeC{l}_3$ is left unreacted
• D. All the above

Answer 1

The correct option is D All the above

The reaction is $FeC{l}_3+3NaOH\to Fe(OH{)}_3+3NaCl$.

Thus, $1$ mole of ferric chloride will react with $3$ moles of $NaOH$ to form one mole of ferric hydroxide.

$0.24$ moles of sodium hydroxide will react with $0.08$ moles of ferric chloride to form $0.08$ moles of ferric hydroxide.

The unreacted amount of ferric chloride is $0.2-0.08=0.12$ moles.

In this reaction, sodium hydroxide is the limiting reagent.