A solution containing $0.319 g$ of complex $C r C l_{3} .6 H_{2} O$ was passed through cation exchanger and the solution given out was neutralised by $28.5 m L$ of $0.125 M N a O H$ . What is the correct formula of complex ?

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Solution

The $C l$ atoms outside the co - ordination sphere will be ionised to produce acid $H C l$

Thus , Meq. of $C l^{-}$ ions outside = Meq. of $H C l$ formed

= Meq. of $N a O H$ formed

= $28.5 \times 0.125$

= $3.56$

$\frac{0.319}{266.5}$ mole or $1.197 m$ mole of complex produce $3.56$ Meq. or millimoles small of $C l^{-}$ .

Thus $1$ mole of complex will give $3$ mole of $C l^{-}$ i.e., all the three Cl atoms are outside the co -ordination sphere .

Thus ,complex is $[C r (H_{2} O)_{6}] C l_{3}$

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