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Question

A solution containing 1 mol per litre of each Cu(NO3)2,AgNO3, and Hg2(NO3)2 is being electrolyzed by using inert electrodes. The values of standard electrode potentials in volts (reduction potential) are
Ag|Ag=+0.80,2Hg|Hg2+2=+0.79
Cu|Cu2+=+0.34,Mg|Mg2+=2.37
with increasing voltage, the sequence of deposition of metals at the cathode will be
(IIT-JEE, 1984)

A
Ag,Hg,Cu,Mg
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B
Mg,Cu,Hg,Ag
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C
Ag,Hg,Cu
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D
Cu,Hg,Ag
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Solution

The correct option is A Ag,Hg,Cu,Mg
Higher the oxidation potential, more easily it is oxidized and faster is the deposition of metal.
Decreasing order of Eoxidation is:
EAg|Ag(0.80)>E2Hg|Hg2+2(0.79)>ECu|Cu2+(0.34)>EMg|Mg2+(2.37)
Hence, the sequence of deposition of metals at the cathode will be Ag, Hg, and Cu.

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