A solution containing 10-0 millimoles of CaCl2 is diluted to 1 L- The number of grams of CaCl2- 2H2O per mL of the final solution is x- 10-3g mL-1- Then- the nearest integer of 2x is -

10 millimoles of #160; CaCl_2· 2H_2O in 1000 mL . ∴ millimoles per mL=101000=0.01 . #160; #160; =0.01× 10^ 3 mol. #160; ...

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Standard XII

Chemistry

Significant Figures

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Question

A solution containing $10.0$ millimoles of $C a C l_{2}$ is diluted to $1$ L. The number of grams of $C a C l_{2} \cdot 2 H_{2} O$ per mL of the final solution is $x \times 10^{- 3} g$ $m L^{- 1}$ . Then, the nearest integer of $2 x$ is :

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Solution

$10$ millimoles of $C a C l_{2} \cdot 2 H_{2} O$ in $1000 m L$ .
$∴$ millimoles per $m L = \frac{10}{1000} = 0.01$ .
$= 0.01 \times 10^{- 3}$ mol.
$= 1 \times 10^{- 5}$ mol.
Mass of $C a C l_{2} \cdot 2 H_{2} O$ per $m L = 147 \times 10^{- 5} g$ $m L^{- 1}$ .
$= 1.47 \times 10^{- 3} g$ $m L^{- 1}$ .
So, $x$ is $1.47$ .

So, $2 x \approx 3$ .

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A solution containing 10.0 millimoles of CaCl2 is diluted to 1 L. The number of grams of CaCl2⋅2H2O per mL of the final solution is x×10−3g mL−1. Then, the nearest integer of 2x is :

10 millimoles of CaCl2⋅2H2O in 1000 mL.∴ millimoles per mL=101000=0.01. =0.01×10−3 mol. =1×10−5 mol.Mass of CaCl2⋅2H2O per mL=147×10−5g mL−1. =1.47×10−3g mL−1.So, x is 1.47.So, 2x≈3.

A solution containing $10.0$ millimoles of $C a C l_{2}$ is diluted to $1$ L. The number of grams of $C a C l_{2} \cdot 2 H_{2} O$ per mL of the final solution is $x \times 10^{- 3} g$ $m L^{- 1}$ . Then, the nearest integer of $2 x$ is :