A solution containing $10 g d m^{- 3}$ of urea (molecular mass = $60 g m o l^{- 1})$ is isotonic with a $5 %$ solution of a nonvolatile solute. The molecular mass of this is nonvolatile solute is:

250 g m o l^{- 1}

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300 g m o l^{- 1}

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350 g m o l^{- 1}

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200 g m o l^{- 1}

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Solution

The correct option is B $300 g m o l^{- 1}$
Molar concentration of urea solution
$= \frac{10 g / d m^{3}}{M o l . w t . o f u r e a}$
$= \frac{10}{60} M = \frac{1}{6}$
Molar concentration of 5% non - volatile solute
$= \frac{50 g / d m^{3}}{M o l . w t . 0 f n o n - v o l a t i l e s o l u t e}$
$= 50 M / m$
Both solutions are isotonic to each other, therefore,
$1 / 6 = 5 / m$
$m = 50 \times 6 = 300 g m o l^{-} 1$

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