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Question

# A solution containing 2.675 g of CoCl3.6NH3 (Molar mass = 267.5 g/mol) is passed through a cation exchanger. The chloride ions obtained in the solution is treated with an excess of AgNO3 to give 4.78 g of AgCl (Molar mass = 143.5 g/mol). The formula of the complex is: (Atomic mass of Ag = 108 u)

A
[CoCl3(NH3)3]
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B
[CoCl(NH3)5]Cl2
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C
[Co(NH3)6]Cl3
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D
[CoCl2(NH3)4]Cl
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Solution

## The correct option is C [Co(NH3)6]Cl3Moles of complex =2.675267.5=0.01 Moles of AgCl precipitated =4.78143.5=0.03 ∴Cl− ions produced = 0.03 moles. It shows that 3 moles of Cl− ions are produced per mole of complex i.e., 3 Cl− ions are present outside the sphere. ∴ The possible structure of complex is [Co(NH3)6]Cl3. [Co(NH3)6]Cl3→[Co(NH3)6]3++3Cl−

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